- Category
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- Hand Operated (81)
- Foot Operated (2)
- Air Powered (106)
- Electric Powered (214)
- Battery Powered (13)
- Gas Powered (29)
- Intensifier (4)
- Accessories (120)
Pumps
Questions to ask yourself
Click on the question to view resources to help you answer.The amount of force a hydraulic cylinder can generate is equal to the hydraulic pressure times the "effective area" of the cylinder.
| FORCE (F) | = | PRESSURE (P) | X | CYLINDER EFFECTIVE AREA (A) |
Example 1
An RC-106 cylinder with 2.24 in2 effective area operating at 8,000 psi will generate what force?
Force = 8,000 psi x 2.24 in2 = 17,920 lbs.
Example 2
An RC-106 cylinder lifting 14,000 lbs will require what pressure?
Pressure = 14,000 lbs ÷ 2.24 in2 = 6,250 psi.
Example 3
An RC-256 cylinder is required to produce a force of 41,000 lbs.
What pressure is required?
Pressure = 41,000 lbs. ÷ 5.15 in2 = 7961 psi.
Example 4
Four RC-308 cylinders are required to produce a force of 180,000 lbs. What pressure is required?
Pressure = 180,000 lbs ÷ (4 x 6.49 in2) = 6933 psi. Remember, since four cylinders are used together, the area for one cylinder must be multiplied by the number of cylinders used.
Example 5
A CLL-2506 cylinder is going to be used with a power source that is capable of 7,500 PSI. What is the theoretical force available from that cylinder?
Force = 7,500 psi x 56.79 in2 = 425,925 lbs.
The volume of oil required for a cylinder (cylinder oil capacity) is equal to the effective area of the cylinder times the stroke.
| CYLINDER OIL CAPACITY | = | CYLINDER EFFECTIVE AREA | X | CYLINDER STROK |
Example 1:
An RC-158 cylinder with 3.14 in2 effective area and an 8 in stroke will require what volume of oil?
Oil Capacity = 3.14 in2 x 8 in = 25.12 in3
Example 2: An RC-5013 cylinder has an effective area of 11.05 in2 and a stroke of 13.25 in. How much oil will be required?
Oil Capacity = 11.05 in2 x 13.25 in = 146.41 in3
Example 3: An RC-10010 cylinder has an effective area of 20.63 in2 and a stroke of 10.25 in. How much oil will it require?
Oil Capacity = 20.63 in2 x 10.25 in = 211.46 in3
Example 4: Four RC-308 cylinders are being used, each with an effective area of 6.49 in2 and stroke of 8.25 in. How much oil will be required?
Oil Capacity = 6.49 in2 x 8.25 in = 53.54 in3 for one cylinder Multiply by four to obtain the required capacity: 214.17 in3
Air/Hydraulic. Uses shop air or a portable air compressor.
Electric /Hydraulic. What voltage is available? Is a battery operated pump preferred?
Gasoline Engine/Hydraulic. Powers high-output pumps at remote job sites where air or electricity are unavailable.
If so, consider a battery pump.
Think about how your pump will be used. If the pump is planned for high-cycle operations, make sure that the pump description says that it can be used for extended duty or high-cycle operation.
Use either a hand/foot pump or air pump. If the pump must operate in a spark-free environment, let Titanply know to tell manufacturer.
Manufacturers Pump Series by Sub-Category
| BVA | ENERPAC | POWER TEAM | SIMPLEX | |
| Hand Operated | P Series | P Series MP Series P/11 Series |
P Series | P Series |
| Foot Operated | P59F | |||
| Air Powered | PA Series PAR Series |
PA Series PAM Series XA Series ZA4 Series |
PA6 Series PA6D Series PA9 Series PA60 Series PA50 Series PA17 Series PA46/55 Series PUA/PMA Series |
PA90 PAM Series |
| Electric Powered | PEW Series PES Series PED Series |
PU Series PE Series ZU Series ZE Series |
PE Series PED Series PQ60 Series PQ120 Series PE-NUT Series |
PED Series PEM Series PES Series |
| Battery Powered | BP Series | PE10 Series | ||
| Gas Powered | PG Series | PGM Series ZG Series |
PG Series | PGM Series |
| Intensifiers | HB Series |
